Congrats on your new baby!
If you have put Snowshoe Choco and Foxie Auburn together for the priority dominance testing for the Saga project testing, then pairing it back to mom may not be the best way to make a proof.
Doing backbreeding is best for when you want to get a particular trait and you are pairing a shown parent to a possible hid child raises the percentage of getting the fur to 50% or higher. It is good for when you want something but it's not the best for testing dominance.
When you are doing dominance, if you have a Foxie Auburn child and want to find out if it has Snowshoe Chocolate hid, the more optimum thing to do is to breed it to something that is known to be more recessive. In this case, Russian Blue and anything more recessive to Russian Blue showing on the partner would be optimal.
Example visually:
A=Foxie Auburn fur (orig dad)
a=Bali Cream or more recessive (orig dad's hid)
B=Snowshoe Choco (orig mom)
b=Russian Black or more recessive (orig mom's hid)
Aa+Bb = child A? (? = B or b)
The reason is if you breed a Foxie Auburn fur shown possible Snowshoe Chocolate hid to a Snowshoe Chocolate shown partner, when you get a Snowshoe Chocolate shown baby you will not know if the Snowshoe Chocolate comes from the partner or is the possible hid from your Foxie Auburn. So you don't have a proof.
B? = unknown partner with Snowshoe chocolate shown)
A?+B? = child B? (B: Snowshoe choclate -- could have come partner or from that first child)
If you pair the Foxie Auburn fur shown possible Snowshoe Chocolate hid to a Foxie Salt&Pepper partner (Foxie S&P is recessive to Russian Blue), when you get a Snowshoe Chocolate shown baby, then you have positive proof Snowshoe Chocolate is recessive to Foxie Auburn. If you get another fur more recessive than Russian Blue like Russian Black, then you know the Foxie Auburn fur shown possible Snowshoe Chocolate hid got the Snowshoe Chocolate hid and not the Snowshoe Chocolate shown.
Foxie S&P = C
Foxie S&P hid = Tonki New Mink (for example)=c
A? + Cd = BC (since B is less than C, B has to come from A because B is dominant to C or C's hid d)
A? = AB positive proof
Hope that helps if you are doing dominance testing. Dominance testing is a little different. Most times if you are doing a backbreed parent to child breeding in dominance testing, it is the most recessive to the most recessive to prove something is more recessive than that most recessive like backbreeding Exotic Journey to pull out Galaxy Star. Anything more dominant than most recessive has other possible variables of a lot of other furs/eyes/traits.
Sorry this is so long but there might be others doing dominance testing or finding their hids and are new to this so I was trying to be clear.
And to anyone who is new, the best reference on eyes and furs on dominance is saga's charts here:
https://drive.google.com/drive/folders/0...ljODliMDhm
(07-28-2016 05:15 PM)Deidra Loring Wrote: Snowshoe Choco vs. Foxie Auburn.
Opened male Foxie Auburn offspring to breed back to Snowshoe Choco mom.